Let's look at interfacing a Hex keypad, the one with 16 switches; arranged in 4 columns and 4 rows. The interesting challenge is to interface 16 switches on 8 pins. So how does this work? The simple answer is the MCU is faster than the your fingers.
Basics
Code
- #include "keypad.h"
- #include "lcd.h"
- int main()
- {
- uint8_t key;
- /*Connect RS->PB0, RW->PB1, EN->PB2 and data bus PORTB.4 to PORTB.7*/
- LCD_SetUp(PB_0,PB_1,PB_2,P_NC,P_NC,P_NC,P_NC,PB_4,PB_5,PB_6,PB_7);
- LCD_Init(2,16);
- /*Connect R1->PD0, R2->PD1, R3->PD2 R4->PD3, C1->PD4, C2->PD5 C3->PD6, C4->PD7 */
- KEYPAD_Init(PD_0,PD_1,PD_2,PD_3,PD_4,PD_5,PD_6,PD_7);
- LCD_Printf("Key Pressed:");
- while (1)
- {
- key = KEYPAD_GetKey();
- LCD_GoToLine(1);
- LCD_DisplayChar(key);
- }
- return (0);
- }
Let's look at the most important function in the code in a little more details
- key = KEYPAD_GetKey();
As you can guess, the function return the ASCII value of the key being pressed. It is defined in keypad.c as below:
- uint8_t KEYPAD_GetKey(void)
- {
- uint8_t i,j,v_KeyPressed_u8 = 0;
- keypad_WaitForKeyRelease();
- keypad_WaitForKeyPress();
- for (i=0;i<C_MaxRows_U8;i++)
- {
- GPIO_PinWrite(A_RowsPins_U8[i],HIGH);
- }
- for (i=0;(i<C_MaxRows_U8);i++)
- {
- GPIO_PinWrite(A_RowsPins_U8[i],LOW);
- for(j=0; (j<C_MaxCols_U8); j++)
- {
- if(GPIO_PinRead(A_ColsPins_U8[j]) == 0)
- {
- v_KeyPressed_u8 = 1;
- break;
- }
- }
- if(v_KeyPressed_u8 ==1)
- {
- break;
- }
- GPIO_PinWrite(A_RowsPins_U8[i],HIGH);
- }
- if(i<C_MaxRows_U8)
- v_KeyPressed_u8 = A_KeyLookUptable_U8[i][j];
- else
- v_KeyPressed_u8 = C_DefaultKey_U8;
- return v_KeyPressed_u8;
- }